[FIX] website: don't suffix cloned menu/page with 'Copy'
This behavior is useless in the front end (`clone_page`) as people cloning a page will leave the page with copy in the page name without even noticing it. Furthermore, creating or copying a website will bootstrap (clone) some pages, suffixing all of these page by 'Copy'.
This commit is contained in:
committed by
Jeremy Kersten
parent
8c701f2c9b
commit
f6e4f3aa0f
@@ -986,7 +986,6 @@ class Page(models.Model):
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new_view = view.copy({'website_id': default.get('website_id')})
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default['view_id'] = new_view.id
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default['name'] = default.get('name', '%s %s' % (self.name, _('(copy)')))
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default['url'] = default.get('url', self.env['website'].get_unique_path(self.url))
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return super(Page, self).copy(default=default)
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@@ -996,15 +995,14 @@ class Page(models.Model):
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:param page_id : website.page identifier
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"""
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page = self.browse(int(page_id))
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new_page = page.copy(dict(website_id=self.env['website'].get_current_website().id))
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new_page = page.copy(dict(name=page.name, website_id=self.env['website'].get_current_website().id))
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# Should not clone menu if the page was cloned from one website to another
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# Eg: Cloning a generic page (no website) will create a page with a website, we can't clone menu (not same container)
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if clone_menu and new_page.website_id == page.website_id:
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menu = self.env['website.menu'].search([('page_id', '=', page_id)], limit=1)
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if menu:
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# If the page being cloned has a menu, clone it too
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new_menu = menu.copy()
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new_menu.write({'url': new_page.url, 'name': '%s %s' % (menu.name, _('(copy)')), 'page_id': new_page.id})
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menu.copy({'url': new_page.url, 'name': menu.name, 'page_id': new_page.id})
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return new_page.url + '?enable_editor=1'
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