[IMP] base: prefetch actions models in batch during /web menus loading

Gain of ~80% of the SQL queries & ~50% of execution time in a database
with test_main_flows & dependencies installed.

On a benchmark of 100 calls of (load_menus(True) + load_menus(False))

* 266 > 56 queries
* 0.38 > 0.21 sec of execution (mean)

Note that this only impacts the first request since this method is cached.
Unless user groups (or debug status) are different, the cached results
are returned.

closes odoo/odoo#83172

Signed-off-by: Raphael Collet <rco@odoo.com>

odoo/addons/base/models/ir_ui_menu.py

@@ -2,6 +2,7 @@
 # Part of Odoo. See LICENSE file for full copyright and licensing details.
 
 import base64
+from collections import defaultdict
 import operator
 import re
 
@@ -93,15 +94,22 @@ class IrUiMenu(models.Model):
 
         # process action menus, check whether their action is allowed
         access = self.env['ir.model.access']
-        MODEL_GETTER = {
-            'ir.actions.act_window': lambda action: action.res_model,
-            'ir.actions.report': lambda action: action.model,
-            'ir.actions.server': lambda action: action.model_id.model,
+        MODEL_BY_TYPE = {
+            'ir.actions.act_window': 'res_model',
+            'ir.actions.report': 'model',
+            'ir.actions.server': 'model_name',
         }
+
+        # performance trick: determine the ids to prefetch by type
+        prefetch_ids = defaultdict(list)
+        for action in action_menus.mapped('action'):
+            prefetch_ids[action._name].append(action.id)
+
         for menu in action_menus:
-            get_model = MODEL_GETTER.get(menu.action._name)
-            if not get_model or not get_model(menu.action) or \
-                    access.check(get_model(menu.action), 'read', False):
+            action = menu.action
+            action = action.with_prefetch(prefetch_ids[action._name])
+            model_name = action._name in MODEL_BY_TYPE and action[MODEL_BY_TYPE[action._name]]
+            if not model_name or access.check(model_name, 'read', False):
                 # make menu visible, and its folder ancestors, too
                 visible += menu
                 menu = menu.parent_id