[FIX] website: don't force website_id on view in all cases
It make test of studio red, and better to have website broken that studio
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@@ -30,13 +30,6 @@ class View(models.Model):
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for view in self:
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view.first_page_id = self.env['website.page'].search([('view_id', '=', view.id)], limit=1)
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@api.model
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def create(self, vals):
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website = self.env['website'].get_current_website(fallback=False)
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if website and 'website_id' not in vals and 'not_force_website_id' not in self.env.context:
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vals['website_id'] = website.id
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return super(View, self).create(vals)
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@api.multi
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def write(self, vals):
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'''COW for ir.ui.view. This way editing websites does not impact other
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