[FIX] packaging: correct docker build name

This commit is contained in:
Christophe Simonis
2016-10-05 20:59:43 +02:00
parent f18def7175
commit 18cdce919b
+4 -3
View File
@@ -272,6 +272,7 @@ def build_exe(o):
# Stage: testing
#----------------------------------------------------------
def _prepare_testing(o):
docker_version = version.replace('+', '')
if not o.no_tarball:
subprocess.call(["mkdir", "docker_src"], cwd=o.build_dir)
subprocess.call(["cp", "package.dfsrc", os.path.join(o.build_dir, "docker_src", "Dockerfile")],
@@ -279,7 +280,7 @@ def _prepare_testing(o):
# Use rsync to copy requirements.txt in order to keep original permissions
subprocess.call(["rsync", "-a", "requirements.txt", os.path.join(o.build_dir, "docker_src")],
cwd=os.path.join(o.odoo_dir))
subprocess.call(["docker", "build", "-t", "odoo-%s-src-nightly-tests" % version, "."],
subprocess.call(["docker", "build", "-t", "odoo-%s-src-nightly-tests" % docker_version, "."],
cwd=os.path.join(o.build_dir, "docker_src"))
if not o.no_debian:
subprocess.call(["mkdir", "docker_debian"], cwd=o.build_dir)
@@ -288,13 +289,13 @@ def _prepare_testing(o):
# Use rsync to copy requirements.txt in order to keep original permissions
subprocess.call(["rsync", "-a", "requirements.txt", os.path.join(o.build_dir, "docker_debian")],
cwd=os.path.join(o.odoo_dir))
subprocess.call(["docker", "build", "-t", "odoo-%s-debian-nightly-tests" % version, "."],
subprocess.call(["docker", "build", "-t", "odoo-%s-debian-nightly-tests" % docker_version, "."],
cwd=os.path.join(o.build_dir, "docker_debian"))
if not o.no_rpm:
subprocess.call(["mkdir", "docker_fedora"], cwd=o.build_dir)
subprocess.call(["cp", "package.dffedora", os.path.join(o.build_dir, "docker_fedora", "Dockerfile")],
cwd=os.path.join(o.odoo_dir, "setup"))
subprocess.call(["docker", "build", "-t", "odoo-%s-fedora-nightly-tests" % version, "."],
subprocess.call(["docker", "build", "-t", "odoo-%s-fedora-nightly-tests" % docker_version, "."],
cwd=os.path.join(o.build_dir, "docker_fedora"))
def test_tgz(o):