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!4965 添加功能

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Merge pull request !4965 from 李鹏宇/dev_zhou
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李鹏宇
2025-09-08 01:54:41 +00:00
committed by Gitee
parent 40c458c85c 3c47f20ca2
commit e484bd68bc
1 changed files with 23 additions and 14 deletions
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yuthon_hr_attendance/models/hr_attendance.py
+23 -14
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@@ -112,25 +112,34 @@ class HrAttendance(models.Model):
record.is_last_month = (first_day_last_month <= record.current_data <= last_day_last_month)
def compute_company_id(self):
employee_date_records = {}
for att in self.env["hr.attendance"].browse(self._context.get('active_ids', self._context.get('active_id'))):
date_records = {}
# 获取记录的日期（忽略时间部分）
record_date = att.current_data if att.current_data else None
if record_date:
# 将记录按日期分组
if record_date not in date_records:
date_records[record_date] = []
date_records[record_date].append(att.id)
if not (att.employee_id and att.current_data):
continue # 跳过缺少员工或日期的记录
# 处理重复记录：每组保留第一条，删除其余
for date, record_ids in date_records.items():
if len(record_ids) > 1:
# 保留第一条记录，删除其余
ids_to_keep = record_ids[0]
ids_to_delete = record_ids[1:]
# 获取员工ID和记录日期（忽略时间部分）
employee_id = att.employee_id.id
# 创建唯一分组键 (员工ID, 日期)
group_key = (employee_id, att.current_data)
# 将记录按员工+日期分组
if group_key not in employee_date_records:
employee_date_records[group_key] = []
employee_date_records[group_key].append(att.id)
# 处理重复记录：每个员工每天只保留第一条记录
for (employee_id, date), record_ids in employee_date_records.items():
if len(record_ids) > 1:
# 保留第一条记录，其余标记为删除
ids_to_keep = record_ids[0]
ids_to_delete = record_ids[1:]
# 执行删除操作
if ids_to_delete:
self.env["hr.attendance"].browse(ids_to_delete).unlink()
# @api.model
# def web_read_group(self, domain, fields, groupby, limit=None, offset=0, orderby=False, lazy=True):
# result = super().web_read_group(domain, fields, groupby, limit, offset, orderby, lazy)