Files
odoo_source/addons/website/models/website_menu.py
T
Romain Derie ea3a2ab678 [IMP] website: show website name in ir.ui.view name_get
Before this commit, it was impossible to know which view was the one searched
if there was COW views.

Indeed, since multiwebsite, views might get duplicated from one website to
another. Then, when searching for an ir.ui.view in a form view, every
duplicated view would be listed next to each other with the exact same name
without a way to identify which one comes from which website.

This commit will suffix the view name by its website_id if there is one.

To do so, we use the context key that has been introduced with 62d73253f3.

task-1920052

closes odoo/odoo#33307

Signed-off-by: Jérémy Kersten (jke) <jke@openerp.com>
2019-07-01 09:48:57 +00:00

168 lines
6.9 KiB
Python

# -*- coding: utf-8 -*-
# Part of Odoo. See LICENSE file for full copyright and licensing details.
from odoo import api, fields, models
class Menu(models.Model):
_name = "website.menu"
_description = "Website Menu"
_parent_store = True
_order = "sequence, id"
def _default_sequence(self):
menu = self.search([], limit=1, order="sequence DESC")
return menu.sequence or 0
name = fields.Char('Menu', required=True, translate=True)
url = fields.Char('Url', default='')
page_id = fields.Many2one('website.page', 'Related Page', ondelete='cascade')
new_window = fields.Boolean('New Window')
sequence = fields.Integer(default=_default_sequence)
website_id = fields.Many2one('website', 'Website')
parent_id = fields.Many2one('website.menu', 'Parent Menu', index=True, ondelete="cascade")
child_id = fields.One2many('website.menu', 'parent_id', string='Child Menus')
parent_path = fields.Char(index=True)
is_visible = fields.Boolean(compute='_compute_visible', string='Is Visible')
group_ids = fields.Many2many('res.groups', string='Visible Groups',
help="User need to be at least in one of these groups to see the menu")
@api.multi
def name_get(self):
if not self._context.get('display_website') and not self.env.user.has_group('website.group_multi_website'):
return super(Menu, self).name_get()
res = []
for menu in self:
menu_name = menu.name
if menu.website_id:
menu_name += ' [%s]' % menu.website_id.name
res.append((menu.id, menu_name))
return res
@api.model
def create(self, vals):
''' In case a menu without a website_id is trying to be created, we duplicate
it for every website.
Note: Particulary useful when installing a module that adds a menu like
/shop. So every website has the shop menu.
Be careful to return correct record for ir.model.data xml_id in case
of default main menus creation.
'''
# Only used when creating website_data.xml default menu
if vals.get('url') == '/default-main-menu':
return super(Menu, self).create(vals)
if 'website_id' in vals:
return super(Menu, self).create(vals)
elif self._context.get('website_id'):
vals['website_id'] = self._context.get('website_id')
return super(Menu, self).create(vals)
else:
# create for every site
for website in self.env['website'].search([]):
w_vals = dict(vals, **{
'website_id': website.id,
'parent_id': website.menu_id.id,
})
res = super(Menu, self).create(w_vals)
# if creating a default menu, we should also save it as such
default_menu = self.env.ref('website.main_menu', raise_if_not_found=False)
if default_menu and vals.get('parent_id') == default_menu.id:
res = super(Menu, self).create(vals)
return res # Only one record is returned but multiple could have been created
@api.multi
def unlink(self):
default_menu = self.env.ref('website.main_menu', raise_if_not_found=False)
menus_to_remove = self
for menu in self.filtered(lambda m: default_menu and m.parent_id.id == default_menu.id):
menus_to_remove |= self.env['website.menu'].search([('url', '=', menu.url),
('website_id', '!=', False),
('id', '!=', menu.id)])
return super(Menu, menus_to_remove).unlink()
@api.one
def _compute_visible(self):
visible = True
if self.page_id and not self.page_id.sudo().is_visible and not self.user_has_groups('base.group_user'):
visible = False
self.is_visible = visible
@api.model
def clean_url(self):
# clean the url with heuristic
if self.page_id:
url = self.page_id.sudo().url
else:
url = self.url
if url and not self.url.startswith('/'):
if '@' in self.url:
if not self.url.startswith('mailto'):
url = 'mailto:%s' % self.url
elif not self.url.startswith('http'):
url = '/%s' % self.url
return url
# would be better to take a menu_id as argument
@api.model
def get_tree(self, website_id, menu_id=None):
def make_tree(node):
page_id = node.page_id.id if node.page_id else None
is_homepage = page_id and self.env['website'].browse(website_id).homepage_id.id == page_id
menu_node = dict(
id=node.id,
name=node.name,
url=node.page_id.url if page_id else node.url,
new_window=node.new_window,
sequence=node.sequence,
parent_id=node.parent_id.id,
children=[],
is_homepage=is_homepage,
)
for child in node.child_id:
menu_node['children'].append(make_tree(child))
return menu_node
if menu_id:
menu = self.browse(menu_id)
else:
menu = self.env['website'].browse(website_id).menu_id
return make_tree(menu)
@api.model
def save(self, website_id, data):
def replace_id(old_id, new_id):
for menu in data['data']:
if menu['id'] == old_id:
menu['id'] = new_id
if menu['parent_id'] == old_id:
menu['parent_id'] = new_id
to_delete = data['to_delete']
if to_delete:
self.browse(to_delete).unlink()
for menu in data['data']:
mid = menu['id']
# new menu are prefixed by new-
if isinstance(mid, str):
new_menu = self.create({'name': menu['name'], 'website_id': website_id})
replace_id(mid, new_menu.id)
for menu in data['data']:
menu_id = self.browse(menu['id'])
# if the url match a website.page, set the m2o relation
# except if the menu url is '#', meaning it will be used as a menu container, most likely for a dropdown
if menu['url'] == '#':
if menu_id.page_id:
menu_id.page_id = None
else:
page = self.env['website.page'].search(['|', ('url', '=', menu['url']), ('url', '=', '/' + menu['url'])], limit=1)
if page:
menu['page_id'] = page.id
menu['url'] = page.url
elif menu_id.page_id:
menu_id.page_id.write({'url': menu['url']})
menu_id.write(menu)
return True