Timer test relies on setTimeout(..., 0) for its execution and its verification. However it seems that in the browser there is *not always* a guarantee that 2 setTimeout(...,0) will execute in a specific order. Delaying the verification by 1 ms : setTimeout(..., 1) should force the order of execution. closes odoo/odoo#41732 Signed-off-by: VincentSchippefilt <VincentSchippefilt@users.noreply.github.com>
80 lines
1.7 KiB
JavaScript
80 lines
1.7 KiB
JavaScript
odoo.define('mail.model.TimerTests', function (require) {
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"use strict";
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var testUtils = require("web.test_utils");
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var Timer = require('mail.model.Timer');
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var concurrency = require('web.concurrency');
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QUnit.module('mail', {}, function () {
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QUnit.module('model', {}, function () {
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QUnit.module('Timer');
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QUnit.test('start()', async function (assert) {
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assert.expect(2);
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var prom = testUtils.makeTestPromise();
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var t = new Timer({
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duration: 0,
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onTimeout: prom.resolve,
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});
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assert.verifySteps([], "should not have called the function");
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t.start();
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await prom;
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assert.ok(true, "should have called the function");
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});
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QUnit.test('clear()', function (assert) {
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var done = assert.async();
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assert.expect(1);
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var func = function () {
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assert.step('function_called');
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};
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var t = new Timer({
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duration: 0,
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onTimeout: func,
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});
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t.start();
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t.clear();
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// Called after timer timeout
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setTimeout(function () {
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assert.verifySteps([], "should not have called the function");
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done();
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}, 1);
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});
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QUnit.test('reset()', async function (assert) {
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assert.expect(4);
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var i = 0;
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var func = function () {
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++i;
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assert.step('function_called ' + i);
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};
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var t = new Timer({
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duration: 0,
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onTimeout: func,
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});
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t.start();
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// Called after 1st timer timeout
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await concurrency.delay(1);
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assert.verifySteps(['function_called 1'], "should have called the function once");
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t.reset();
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// Called after 2nd timer timeout
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await concurrency.delay(1);
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assert.verifySteps(['function_called 2'],
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"should have called the function twice (2nd time from reset)");
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});
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});
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});
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});
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