Files
odoo_source/addons/hr_payroll/security/hr_payroll_security.xml
T
Raphael Collet 2f7c03d9ca [IMP] base: add regular user admin as uid 2
User 1 simply becomes a technical user (inactive, no password).
2018-08-23 21:38:57 +02:00

38 lines
1.7 KiB
XML

<?xml version="1.0" encoding="utf-8"?>
<odoo>
<data noupdate="1">
<record id="group_hr_payroll_user" model="res.groups">
<field name="name">Officer</field>
<field name="category_id" ref="base.module_category_hr_payroll"/>
<field name="implied_ids" eval="[(4, ref('hr.group_hr_user')), (4, ref('hr_contract.group_hr_contract_manager'))]"/>
</record>
<record id="group_hr_payroll_manager" model="res.groups">
<field name="name">Manager</field>
<field name="category_id" ref="base.module_category_hr_payroll"/>
<field name="implied_ids" eval="[(4, ref('hr_payroll.group_hr_payroll_user'))]"/>
<field name="users" eval="[(4, ref('base.user_root')), (4, ref('base.user_admin'))]"/>
</record>
<record id="base.default_user" model="res.users">
<field name="groups_id" eval="[(4,ref('hr_payroll.group_hr_payroll_manager'))]"/>
</record>
<record id="hr_payroll_rule_officer" model="ir.rule">
<field name="name">Officer and subordinates Payslip</field>
<field name="model_id" ref="model_hr_payslip"/>
<field name="domain_force">['|','|', ('employee_id.user_id', '=', user.id), ('employee_id.department_id', '=', False), ('employee_id.department_id.manager_id.user_id', '=', user.id)]</field>
<field name="groups" eval="[(4, ref('hr_payroll.group_hr_payroll_user'))]"/>
</record>
<record id="hr_payslip_rule_manager" model="ir.rule">
<field name="name">All Payslip</field>
<field name="model_id" ref="model_hr_payslip"/>
<field name="domain_force">[(1,'=',1)]</field>
<field name="groups" eval="[(4, ref('hr_payroll.group_hr_payroll_manager'))]"/>
</record>
</data>
</odoo>